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Deadly Triple Shooting In Deerfield Beach

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Deerfield Beach, Florida – On Wednesday in an early morning shooting in Deerfield Beach one man was killed, and two other people were sent to area hospitals.

According to Broward Sheriff’s Office officials, the shooting took place around 2 a.m. near the 600 block of Northeast 40th Street.

Upon arrival, fire rescue crews arrived and found one man with gunshot wounds and transported him to an area hospital. Later he was pronounced dead.

Two other people suffered gunshot wounds and were driven to area hospitals. Officials have not released the identity of the victims at this time.

Anyone with information is asked to call Broward Crime Stoppers at 954-493-TIPS.

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